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andreyandreev [35.5K]
3 years ago
6

What is .00062 as a percent?

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0
The answer would be 0.062%
Alex73 [517]3 years ago
3 0
0.0062 is 0.062%
If this helped smash that thanks button
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Answer:

6 to the power of 2 or 6 squared

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Mislabeled seafood In 2013 the environmental group Oceana (usa.oceana.org) analyzed 1215 samples of seafood purchased across the
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Using the z-distribution, it is found that the 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).

<h3>z-distribution interval:</h3>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

  • In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

For this problem:

  • 1215 samples, hence n = 1215.
  • 33% was mislabeled or misidentified, hence p = 0.33.
  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

<h3>The lower limit of this interval is:</h3>

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.33 - 1.96\sqrt{\frac{0.33(0.67)}{1215}} = 0.3036

<h3>The upper limit of this interval is:</h3>

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.33 + 1.96\sqrt{\frac{0.33(0.67)}{1215}} = 0.3564

The 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).

You can learn more about the use of the z-distribution to build a confidence interval at brainly.com/question/25730047

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The temperature is changing every day by negative 7 over 18 degrees Fahrenheit. What will be the change in the temperature after
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You would multiply the -7 by 3 to come up with -21/18.
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-6.

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To eliminate x the first equation should be multiplied by -6 giving:

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Adding this to the second equation will eliminate x.

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3 years ago
Help 20 points added
Natalija [7]

Answer:

fig 1st 2nd and last

not the third one

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