Answer:
6 to the power of 2 or 6 squared
Using the z-distribution, it is found that the 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
<h3>z-distribution interval:</h3>
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

- In which z is the z-score that has a p-value of
.
For this problem:
- 1215 samples, hence
.
- 33% was mislabeled or misidentified, hence
.
- 95% confidence level, hence
, z is the value of Z that has a p-value of
, so
.
<h3>The lower limit of this interval is:</h3>

<h3>The upper limit of this interval is:</h3>

The 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
You can learn more about the use of the z-distribution to build a confidence interval at brainly.com/question/25730047
You would multiply the -7 by 3 to come up with -21/18.
Answer:
-6.
Step-by-step explanation:
y = x - 6
y = 6x - 19
To eliminate x the first equation should be multiplied by -6 giving:
-6y = -6x + 36
Adding this to the second equation will eliminate x.