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3 years ago

What is .00062 as a percent?

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

The answer would be 0.062%

Alex73 [517]3 years ago

3 0

0.0062 is 0.062%
If this helped smash that thanks button

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At the movie theatre, child admission is $5.10 and adult admission is $9.70. On Thursday, 128 tickets were sold for a total sale

kvv77 [185]

Answer:

Step-by-step explanation:

Let x be the number of children tickets sold and y be the number of adult tickets sold. Then

x+y=128.

The cost of x children tickets is $5.10x and the cost of y adult tickets is $9.70y, so

5.10x+9.70y =896.60.

From the first equation,

x=128-y,

then

$5.10(128-y)+9.70y=896.60,\\ \\652.80-5.10y+9.70y=896.60,\\ \\4.60y=243.8,\\ \\y=53.$

53 adult tickets were sold.

6 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

Please help me i have a couple mins

finlep [7]

Answer:

x + 3

Step-by-step explanation:

Because he bought an unknown number of soccer balls that is where we use the variable, x. And we know that he bought 3 baseballs, and we add them both to get the total number of things bought. Hope this helped and you could give brainliest :)

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3 years ago

Molly started her piano lesson at 3:45 pm the lesson lasted 20 minutes.what time did the piano lesson end?

vova2212 [387]

4:05 pm very simple just add 20 minutes to the time

4 0

3 years ago

Help (picture attached)

Orlov [11]

I have no idea what this means im in 6th grade

5 0

3 years ago