To illustrate the information in the correct syntax:
X~N(23334, 3412²)
What we're being asked to find is P(X ≤ 26000).
In order to do this, we need to convert this value into one we can look up on the table for the standard normal distribution (Z).
To do this we use the formula:
Z = (X - μ)/σ
Z = (26000 - 23334)/3412 = 0.7813599... ⇒ 0.78
We can say:
P(X ≤ 26000) = P(Z ≤ 0.78) = 0.7823
The only possibility would be 1
Answer:
16.3
Step-by-step explanation:
Hope this helps!!
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