Answer:
Let the first equation be x + y = 10
x = 10 -y
2nd equation will be 1x + 1.2y = 11
Substituting in 2nd equation
(10 - y) + 1.2y = 11
10 - y + 1.2y = 11
.2y = 1
y = 5
If y = 5, x = 5: coz x + y = 10
Answer:
x=-4
Step-by-step explanation:
sqrt(x+40) - 17 = -11
Add 17 to each side
sqrt(x+40) - 17+17 = -11+17
sqrt(x+40) = 6
Square each side
(sqrt(x+40) )^2 = 6^2
x+40 = 36
Subtract 40 from each side
x+40-40 = 36-40
x = -4
Answer with Step-by-step explanation:
We are given the table as:
x f(x)
0 6
2 7
4 0
7 5
i.e. corresponding to different values of x we are given the values of f(x)
we have to find the value of f(0)
i.e. we have to find the value of f(x) when x=0
As we can see from the table the value of f(x) at x=0 is 6
Hence, Correct option is:
C) 6
The answer is A. Yes. 6^2 + 8^2 = 10^2
A tangent line usually extends out of the circle and intersects the circle at one point.
hope this helps !
Answer:
I DO LOL
Step-by-step explanation:
sorry for caps