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Evgen [1.6K]
3 years ago
8

A. Plot the data for the functions f(x) and g(x) on a grid (SHOWN ABOVE)

Mathematics
1 answer:
Arada [10]3 years ago
5 0
It would have to be A
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The point (x,y) is proportional to the point (2, 5).
Anna [14]

Answer:

Help

Step-by-step explanation:

3 0
3 years ago
How many real number solutions does the equation have?-8x^2-8x-2=0
Marysya12 [62]
Hello,

I)
1 solution with multiplicity 2
(2x+1)²=0

II) ANSWER C (-4.41, -1.59)
-3-√2 and -3+√2

III)
y=x²+2x
y=3x+20
==>x²+2x=3x+20
==>x²-x-20=

Δ=1+4*20=81=9²

(x=(1-9)/2=-4 and y= 3*(-4)+20=8 ) or (x=(1+9)/2=5 and y=3*5+20=35)


3 0
3 years ago
A wall is 20 feet long and requires 1,470 bricks to build. How high is the wall?
Arte-miy333 [17]

Answer: The height of wall is 10.5 feet.

Step-by-step explanation:

Since we have given that

Number of bricks to build = 1470

Length of wall = 20 feet

We need to find the height of wall.

As we know that

Bricklayer's formula is given by

N=7LH\\\\1470=7\times 20\times H\\\\1470=140\times H\\\\\dfrac{1470}{140}=H\\\\10.5\ ft=H

Hence, the height of wall is 10.5 feet.

3 0
3 years ago
Help me solve please
Triss [41]
I think The answer is 9.24
4 0
3 years ago
Read 2 more answers
Find the probability of getting a 1, 4, or 5 when you roll a standard six-sided die. Give your answer as a simplified fraction.
aivan3 [116]

The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

P=\frac{\text{ favourable cases}}{\text{total amount of cases}}=\frac{3}{6}=\frac{1}{2}

So the probability written as a simplified fraction is 1/2.

6 0
1 year ago
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