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Blizzard [7]
3 years ago
12

Which expression is equivalent to 4(5 − 3) 9 − 3 8x 20 − 12 8 + 1

Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0
The correct answer is 20- 12
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gary mixes a solution using two types of concentration of sale: .70 gallons of 5% and .30 gallons of 22% salt. what is the conce
wolverine [178]

Answer:

10.1%

Step-by-step explanation:

The first thing we should do is calculate the total volume of the solution when mixing them would be:

0.7 + 0.3 = 1

Now, we have that the resulting concentration (x) would be equal to the sum of the multiplications between the volumes and the concentrations to be mixed, as follows:

x * 1 = 0.7 * 0.05 + 0.3 * 0.22

x = 0.035 + 0.066

x = 0.101

That is, the concentration of the resulting mixture would be 10.1% (0.101 * 100)

5 0
3 years ago
To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?
romanna [79]
Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is A=\pi r^2 and denote the sector area as A_1. 
Then  \dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}  (the ratio between area is the same as the ratio between coresponding angles).

A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}.

6 0
3 years ago
What is the center and radius of the circle with equation (x - 2)^2 + (y - 5)^2 = 100?
ololo11 [35]
Answer: 
Center = (2,5)
Radius = 10
Choice A

To find this answer, first write the equation 
(x-2)^2 + (y-5)^2 = 100
into 
(x-2)^2 + (y-5)^2 = 10^2

Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2

We see that (h,k) = (2,5) is the center
and r = 10 is the radius
5 0
3 years ago
Read 2 more answers
A circle has a radius of 9 cm.
stira [4]

Radius = 9cm

So,

Area of circle = πr²

= π(9)²

= π × 81 cm²

= 81π cm²

8 0
3 years ago
Read 2 more answers
Please help extremely confused
svetlana [45]

Answer:

basic geometry and trig ratios

Step-by-step explanation:

sin 10 = 500/x

x = 500/sin 10

x = 2 879,4 m

8 0
2 years ago
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