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3 years ago

X+5=5 What is the value?

Mathematics

2 answers:

dsp733 years ago

6 0

The answer is I also agree 1x or x

AveGali [126]3 years ago

4 0

Answer: 1x or x

X=5-5
=X

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A photographer buys a new camera for $1350. Every year the camera decreases in value by 10%.

bagirrra123 [75]

Answer:

A(t)=1350(0.9)^t

i hope this helps :)

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2 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago

The equation and the variable

pav-90 [236]

Variable: $175=P $40=L $375=TB
x=TB-P/L

Equation: $375-$175/$40=5
This means that the amount of hours you paid for is 5 hours.

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3 years ago

If tommy had 3 x 99 amount of cookies and gave 4x56 away how many does he have left?

Monica [59]

he has 73 cookies left

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2 years ago

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Suppose that I scores have a bell shaped distribution with a mean of 96 and a standard deviation of 14. Using the empirical rule

Diano4ka-milaya [45]

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your answer is already wrong so did not help you

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2 years ago