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ICE Princess25 [194]
3 years ago
13

What computer did d takahashi and y kanada use to calculate pi?

Computers and Technology
1 answer:
Brut [27]3 years ago
8 0
<span>It depends on how much places they calculated to. As far as I remember D</span> Takahashi and Y<span> Kanada</span><span> used HITACHI SR2201 </span>to calculate pi to 5153960000 places and later they used<span> HITACHI SR8000 to calculate pi to</span> 206,158,430,000 places.
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For this project you will write a Java program that will run a simple math quiz. Your program will generate two random integers
ElenaW [278]

Answer:

Here is the JAVA program:

import java.util.Scanner;   //to accept input from user

public class FunWithBranching {   //class name

   public static void main(String[] args) {  //start of main function

   Scanner input = new Scanner(System.in);  //creates Scanner object

   System.out.print("Enter your name: "); //prompts user to enter name

   String userName = input.nextLine();  //stores the name

   System.out.print("Welcome " + userName + "! Please answer the following questions:\n");   //prompts user to answer the questions

   int randomOperand1 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 1 (1-20)

   int randomOperand2 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 2 (1-20)

   int randomAdd = randomOperand1 + randomOperand2;  //performs addition of two random numbers and stores result in randomAdd

   int randomMul = randomOperand1 * randomOperand2;  //performs multiplication of two random numbers

   int randomDiv = randomOperand1 / randomOperand2;  //performs division of two random numbers

   int randomMod = randomOperand1 % randomOperand2;  //performs modulo of two random numbers

   int correctAns = 0;  //stores number of correct answers

   System.out.print(randomOperand1 + " + " + randomOperand2 + " = ");  //displays random number + random number

   int AdditionGuess = input.nextInt();   //reads the answer of addition from user and stores it in AdditionGuess

   if (AdditionGuess == randomOperand1 + randomOperand2) {  //if the user answer is correct

   System.out.println("Correct!");  //displays correct

   correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of addition

 } else {  //if user answer is incorrect

   System.out.println("Wrong!");  //displays wrong

   System.out.println("The correct answer is " + randomAdd);   }  //displays the correct answer of addition

   System.out.print(randomOperand1 + " * " + randomOperand2 + " = ");  //displays random number * random number  

   int MultiplicationGuess = input.nextInt();   //reads the answer of multiplication from user and stores it in MultiplicationGuess

 if (MultiplicationGuess == randomOperand1 * randomOperand2) {  //if the user answer is correct

     System.out.println("Correct!");  //displays correct

     correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of multiplication

 }else{  //if user answer is incorrect

       System.out.println("Wrong!");  //displays wrong

       System.out.println("The correct answer is " + randomMul);   }  //displays the correct answer of multiplication

   System.out.print(randomOperand1 + " / " + randomOperand2 + " = ");  //displays random number / random number  

   int DivisionGuess = input.nextInt();   //reads the answer of division from user and stores it in DivisionGuess

   if (DivisionGuess == randomOperand1 / randomOperand2) {  //if the user answer is correct

       System.out.println("Correct!");  //displays correct

       correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of division

       }else{  //if user answer is incorrect

           System.out.println("Wrong!");  //displays wrong

           System.out.println("The correct answer is " + randomDiv);     }  //displays the correct answer of division

      System.out.print(randomOperand1 + " % " + randomOperand2 + " = ");  //displays random number % random number  

       int ModGuess = input.nextInt();  //reads the answer of modulo from user and stores it in ModGuess

           if (ModGuess == randomOperand1 % randomOperand2) {  //if the user answer is correct

           System.out.println("Correct!");  //displays correct

           correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of modulo

           }else{  //if user answer is incorrect

               System.out.println("Wrong!");  //displays wrong

               System.out.println("The correct answer is " + randomMod);    }  //displays the correct answer of modulo

double percentage = correctAns * 25;   //computes percentage

System.out.println("You got " + correctAns + " correct answers.");   //display number of correct answers given by user

System.out.println("That's " + percentage + "%!");         }  } //displays percentage

Explanation:

The program is well explained in the comments mentioned with each line of code. The screenshot of the output is attached.

3 0
3 years ago
What will be the output of the following code?
mojhsa [17]

Answer:

it schold be C = False di True True

5 0
3 years ago
Jamey did a lot of research on his paper topic but can't figure out where to start writing. He has a loose plan in mind, but it'
Lisa [10]
He should come up with a definite plan.
5 0
3 years ago
Read 2 more answers
To maintain audience interest in a multimedia presentation, use animations or transition features to control when objects or tex
ira [324]

Answer:

True

Explanation:

A "multimedia presentation" refers to a presentation that uses <em>texts, images, audios, animations, photographs and the like </em>in order to help a particular set of audience understand. The presenter's ideas become clear because the audience can deeply grasp the meaning through different graphics and colors presented.

So, <em>the answer above is definitely true</em> because using animations or transitions figures to control when objects or texts appear can <u>prevent boredom</u> on the end of the audience. This will spark interest on their end.

However, it is important not to overdo it because this will cause further distraction that will divert your audience's attention. It should also be <u>conservative and consistent.</u>

4 0
3 years ago
Write a method that takes two circles, and returns the sum of the areas of the circles.
11111nata11111 [884]

Answer:

public static double areaSum(Circle c1, Circle c2){

 double c1Radius = c1.getRadius();

 double c2Radius = c2.getRadius();

 return Math.PI * (Math.pow(c1Radius, 2) + Math.pow(c2Radius, 2));

public static void main(String[] args){

 Circle c1 = new Circle(6.0);

 Circle c2 = new Circle(8.0);

  areaSum(c1,c2);

 }

Explanation:

7 0
2 years ago
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