Question

Please help- geometry

Answer 1

Answer:

$(x+9.3)^2 +(y-4.1)^2 = 13$

How to solve it:

Given that the center of this circle is $C=(-9.3, 4.1)$ and the radius given is $\sqrt{13}$, the standard equation of a circle can be written like this:

$(x-(-9.3))^2 + (y-4.1)^2 = (\sqrt{13})$

This solves into: $(x+9.3)^2 +(y-4.1)^2 = 13$