This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
Pedro scored 1479 points while Ricky scored 1199 points
I think that the first person who came along to buy apples would have to buy 12 dozen apples at $1 per dozen. Paul’s sells one dozen, Nick sells 4 dozen, and Ben sells seven dozen. After that, Paul has 3 apples, Nick has 2, and Ben has 1. If they all sent their remaining apples at a price of $3, Paul would earn 9 more dollars, Nick would earn 6, and Ben would earn three. That puts them each with a profit of $10.
