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Annette [7]
2 years ago
5

If circumference of a circle is 12TT, then its area is 36T. True False

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
4 0

Answer:

True

Step-by-step explanation:

Because yes, idk

azamat2 years ago
4 0

Answer:

true

Step-by-step explanation:

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If A ⊂ B, then which of the following describes the relationship between A and B?
Amanda [17]

A set is a well-defined collection of objects. Each object in a set is called an element of the set. Two sets are equal if they have exactly the same elements in them.

A set is a subset of another set if all elements of the set are elements of the set . In other words, the set is contained inside the set . The subset relationship is denoted as A ⊂ B .The relationship of one set being a subset of another is  also called inclusion  or we can say Set B may have more elements than A does.

Option 4 .Set B may have more elements than A does is the right answer.




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3 years ago
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There are 5 members of a Math Club. In how many ways can the positions of a secretary, a presidents and treasurer be chosen?
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Answer:

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3 0
3 years ago
The grocery store is mile from Katie’s house and the gas station is 0.5 mile from Katie’s house.
Effectus [21]

Answer:

the answer would be a

Step-by-step explanation

you would have to travel a shorter distance to get from katies house to the gasstation.

8 0
3 years ago
I need help please need this answer.
podryga [215]

Answer:

Step-by-step explanation:

The answer is C because if you calculate it then the answer would be 65

8 0
2 years ago
A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
3 years ago
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