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kozerog [31]
3 years ago
11

21. Create an area model to represent 14 X 17. Find the product.

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

14 times 17 is 238.

I will draw an area model and add it to my answer.

Hope this helps!!!

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john is cutting wood planks. He has a 3 foot plank. he needs to cut them in 3/8 length pieces. How many pieces will he have?
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Answer:

he will have 3 pieces

Step-by-step explanation:

3/8×8

=3

<h2>Mark me BRAINLIEST </h2>
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3 years ago
Question 1 : Match the Term with the correct Definition
Alex_Xolod [135]

Answer:

Great Circle - A

Sphere - B

Ellipse - C

Circle - D

Triangle - E

A triangle

A triangle

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3 years ago
What is three hundred thousand, five thousand sixty-three written in standard form
RSB [31]
305,063      Hope this helps!
4 0
4 years ago
Read 2 more answers
How can i find the midpoint of a line segment ?​
eimsori [14]

Answer:

add both x coordinates and divide them by 2.

add both y coordinates and divide them by 2.

Now final product should be (x,y)

Step-by-step explanation:

Example.

let's take 2 points:

(2,5) and (7, 9)

let's add both x coordinates.

2+7 = 9

now add both y coordinates.

5+9 = 14

Now divide both by 2.

Final answer should be (4.5, 7) = this is your midpoint

8 0
3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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