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Bas_tet [7]
3 years ago
6

Asap answer pls -------------------

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

f(2) = - 5

Step-by-step explanation:

Using the recursive rule and f(1) = - 3 , then

f(2) = 2f(1) + 1 = 2 × - 3 + 1 = - 6 + 1 = - 5

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Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

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Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

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Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

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146 °

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