Answer:
The complete program is as follows:
def convert_distance(miles):
km = miles * 1.6 # approximately 1.6 km in 1 mile
return km
my_trip_miles = 55
# 2) Convert my_trip_miles to kilometers by calling the function above
my_trip_km =convert_distance(my_trip_miles) #3) Fill in the blank to print the result of the conversion
# 4) Calculate the round-trip in kilometers by doubling the result,
print("The distance in kilometers is " +str(my_trip_km))
# and fill in the blank to print the result
print("The round-trip in kilometers is " + str(my_trip_km * 2))
Explanation:
<em>The program is self-explanatory because I used the same comments in the original question.</em>
Answer: testing
Explanation:
Testing an answer with multiple attachments
by typing ctrl+ s on keyboard
Answer:
Link-local address
Explanation:
IP addresses that have "FE80" as the hexadecimal representation of their first 10 bits are IPV6 reserved addresses for link-local unicast addressing. These addresses are automatically configured (though may be manually configured too) on any interface and should not be routed. They are used for addressing on a single link with the main aim, among others, of automatic configuration and routing protocol advertisement. Devices attached to this link can be accessed or reached using the link-local addresses as they don't need a global address to communicate.
However, routers will not forward datagram or packets using link-local addresses. In other words, routers are not allowed to connect to the internet using the unicast link-local addresses.
Answer:
1.) Write the formula, which assigns double x to double n raised to the double z power.
Answer: 2\times x → 2\times n^(2\times z<u>)</u>
2.) Write a formula, which will add 5 to the cube of double t times double n, and assign it to double x.
Answer: 5\plus 2\times t^3→2\times x
3.) Write a formula, which will assign double x to square root of the sum of the squares of the lengths of the two legs of a triangle. Declare double leg1, and double leg2, in order to find the hypotenuse. (Pythagorean Theorem)
Answer: 2\times x → \sqrt \{(l^2)_1 + (l^2)_2\}= hypotenuse
4.) Write a program that find the distance between two values on the number line by taking the absolute value of their difference. Assign the answer to double x. The two numbers have been declared as follows:
double num1, num2
Answer: length = \sqrt\{|num2 - num1\|} → 2\times x
Explanation:
