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Marat540 [252]
4 years ago
10

Find the slope of the line that passes through the points (2,12)and(-2,0)

Mathematics
1 answer:
bulgar [2K]4 years ago
7 0

Answer:

m=3

Step-by-step explanation:

to find the slope between two points use the formula m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{0-12}{-2-2}

simplify

m=\frac{-12}{-4}

divide -12 by -4

m=3

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Subtract each number below from the number above.

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a student bought a juice pouch for $2.50 and 3 bags of chips. the total cost was $5.05 write and solve an equation to determine
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First, write it as an equation

2.50+3x=5.05

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3 years ago
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Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
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Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

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f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 6, \sigma = 0.2

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This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

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1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{\sigma}

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This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

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This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

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