3 years ago

In right triangle JFK sin(52)= cos(5x-2). What is the measure of the smallest angle in the triangle?

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer:

48°

Step-by-step explanation:

Given the trigonometry equation

sin(52)= cos(5x-2)...1

According to the quadrant:

Sin(θ) = cos(90-θ)

Sin52 = cos(90-52)

Sin52 = cos48... 2

Substituting 2 into 1:

Cos48 = cos(5x-2)

48 = 5x-2

5x = 48+2

5x = 50

x = 10°

The smallest of the angle will be angle 5x-2 = 5(10)-2

= 50-2

= 48°

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