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3 years ago

Name three points that are collinear. Assume angle TSR is not a straight angle.

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

3 0

Answer:

TS, SR, and TR are all co-linear

Step-by-step explanation:

Regardless of where the points lie, you can connect a line segment from point T to point S, so TS are co-linear

The same goes for point S to point R

The same goes for point T to point R

The definition of a line is the shortest distance through 2 points in space, so you can make a line between any 2 points.

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<h3>Inequalities</h3>

Inequalities is a mathematic expression that do not present equalitiy between both sides. It is represented by symbols: <, ≤, > and ≥.

For solving this exercise, firstly, you should solve the inequalities identified by letters: H, W, M, Y and C. After that, you should relate yours anwers with the options given for the exercise.

Inequality H

$-11x-4 > -15\\ \\ -11x > -15+4\\ \\ -11x > -11\; *(-1)\\ \\ 11x < 11\\ \\ x < 1$

Therefore, you should connect H with x<1.

Inequality W

$32 > -16x\\ \\ Rewriting \\ \\ -16x < 32 \\ \\ -16x < 32\; *(-1)\\ \\ 16x > -32\\ \\ x > \frac{-32}{16} \\ \\ x > -2$

Therefore, you should connect W with x>-2.

Inequality M

$3+x\leq -9\\ \\ x\leq -9-3\\ \\ x\leq -12$

Therefore, you should connect M with x≤-12.

Inequality Y

$-7x+7\leq -56\\ \\-7x\leq -56-7\\ \\ -7x\leq -63\\ \\ -7x\leq -63\; *(-1)\\ \\ 7x\geq 63\\ \\ x\geq \frac{63}{7} \\ \\ x\geq 9$

Therefore, you should connect Y with x≥9.

Inequality C

$-20\geq -5x+15\\ \\Rewriting\\ \\ 5x+15\leq -20\\ \\ -5x\leq -20-15\\ \\ -5x\leq -35\\ \\-5x\leq -35\; *(-1)\\ \\ 5x\geq 35\\ \\ x\geq \frac{35}{5} \\ \\ x\geq 7$

Therefore, you should connect C with x≥7.

Thus, the sequence is:

M - $x\leq -12$

C - $x\geq 7$

Y- $x\geq 9$

H- $x < 1$

W- $x > -2$