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nekit [7.7K]
3 years ago
5

Twice a number is 60 more than five times the number. what is the number?

Mathematics
1 answer:
Delvig [45]3 years ago
5 0
Let the number be represented by x
2x=60+ 5x                          -20*2=60+5*-20
2x-5x=5x-5x+60                     -40=60+-100
-3x=60                                      -40=-40
-3x/-3=60/-3
x=-20
Therefore the number is -20
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slavikrds [6]

Answer:

Shea's coworkers received .89 of a cookie each.

Step-by-step explanation:

18,698/297 = 62.9 rounded to 63

63/71 = .887 rounded to .89

.89 cookies

8 0
3 years ago
Write the product as a sum: 14cos(39x)sin(19x)
charle [14.2K]

Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

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4 0
2 years ago
Josh is trying to factor the expression
mrs_skeptik [129]

Answer:

a) Josh likely made the negative and positive multiplication error.

b) -20a-8+12b

= -4(5a+2-3b)

Step-by-step explanation:

To check if you are correct, you can always simplify it again:

-4(5a+2-3b)

=-20a-8+12b

Remember:

Negative times negative equals to positive, negative times positive equals to negative!

I hope this is helpful! :)

4 0
2 years ago
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mars1129 [50]

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Therefore, ∠EAB, which is ∠A will correspond to ∠T.

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6 0
3 years ago
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