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docker41 [41]
3 years ago
7

Tyson has two movie tickets and wants to randomly select one of six friends to go with him. He rolls a six-sided die to make his

decision. He tested this model 60 times and recorded the results in this table.
Result of Roll Times Result Occurred
1 - 11
1 - 0.18
2 - 9
2 - 0.15
3 - 9
3 - 0.15
4 - 10
4 - 0.17
5 - 11
5 - 0.18
6 - 10
6 - 0.17
Do you think the relative frequency from the experiment is a good predictor of the theoretical probability? Why or why not?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

<u><em>The relative frequency of rolling a particular number can be calculated using the formula </em></u>

<u><em> </em></u>

<u><em>relative frequency , where f is the actual frequency of an event and n is the number of times the experiment is performed. This experiment had the following results: </em></u>

<u><em> </em></u>

<u><em>The relative frequency of rolling a 1 is 0.2. </em></u>

<u><em>The relative frequency of rolling a 2 is about 0.23. </em></u>

<u><em>The relative frequency of rolling a 3 is about 0.13. </em></u>

<u><em>The relative frequency of rolling a 4 is 0.15. </em></u>

<u><em>The relative frequency of rolling a 5 is 0.15. </em></u>

<u><em>The relative frequency of rolling a 6 is about 0.13. </em></u>

<u><em>The relative frequencies of rolling 1, 2, 3, 4, 5, and 6 are quite similar. So, the relative frequency is a good predictor of the theoretical probability. </em></u>

Step-by-step explanation:

this is exact answer from edmentum so change it up a bit

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Answer:

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5 0
3 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
For the linear equation 5x - y = 2, which of the following has a value of 5?
Step2247 [10]

The slope-intercept form of a line is the following:

y=mx+q

In this form, m is the shape and q is the y-intercept. Your line written in this form is

y=5x-2

which implies that the slope is 5 and the y-intercept is -2.

8 0
3 years ago
4. Jen makes a rectangular banner. It is 34 yard long and 14 yard wide. What is the area of the banner in square yards?
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Area = Length x Width 

Area = 34 x 14 

Area = 476 yd²

Answer: 476 yd²
6 0
3 years ago
Read 2 more answers
Jason had three more than four times the amount of money that Jeff has. Together they have $72. How much money does each person
adelina 88 [10]

Answer:

Jason has $58.20 and Jeff has $13.80.

Step-by-step explanation:

Let x represent the amount of money Jason has, and y represent the amount of money Jeff has.

We know that together they have $72. So, we can write the following equation:

x+y=72

We know that Jason has three <em>more</em> than four <em>times</em> the amount of money Jeff has. So:

x=3+4y

This is a system of equations. We can solve it by using substitution. Let's substitute the second equation into the first. This yields:

(3+4y)+y=72

Combine like terms:

5y+3=72

Subtract 3 from both sides:

5y=69

Divide both sides by 5:

y=69/5=\$13.80

So, Jeff has $13.80

We know that Jason has three more than four times the amount of money Jeff has.

Therefore, Jason has:

x=13.8(4)+3

Multiply and add:

x=\$58.20

So, Jason has $58.20 and Jeff has $13.80.

And we're done!

7 0
3 years ago
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