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3 years ago

The greater of two consecutive integers is nine more than twice the lesser integer. What are the two integers?

Mathematics

2 answers:

DaniilM [7]3 years ago

6 0

-7 and -8

This is the answer

MakcuM [25]3 years ago

3 0

Answer:

-7 and -8

Step-by-step explanation:

Generally with this kind of problem it is helpful to construct equations representing the words.

Let's let:

Lesser integer = X

Greater integer = Y

The integers are consecutive, meaning that they are only one integer (number) apart. So,

Y = X+1

From the problem, we know that

Y = 9 + 2X

Now, we can sub in the equation from above.

(X + 1) = 9 + 2X

We now solve for X:

1 - 9 = 2X - X

-8 = X

Y = -8 + 1

Y = -7

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3 years ago

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Nana76 [90]

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3 years ago

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Table B

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

<em>Verify table B</em>

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For $x=2, y=1$ -----> $k=y/x=1/2$

For $x=3, y=3/2$ -----> $k=y/x=(3/2)/3=1/2$

For $x=4, y=2$ -----> $k=y/x=2/4=1/2$

The values of k are the same

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The table B shows y as DIRECTLY PROPORTIONAL to x

<em>Verify table D</em>

For $x=1, y=3$ -----> $k=y/x=3/1=3$

For $x=2, y=5$ -----> $k=y/x=5/2=2.5$

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Step-by-step explanation:

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