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Dima020 [189]
3 years ago
7

The probability of event A is 0.5 and probability of event B is 0.2. Given that A and B are independent, then the probability of

A and B (A intersection B) is:
Mathematics
1 answer:
laiz [17]3 years ago
8 0
If they are independent, then P(A and B) is just P(A) times P(B). Which is 0.5*0.2=0.1
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Simplify the following expression. <br>7^-5/6.7^-7/6. <br>1/49<br>1/14<br>14<br>49
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{7}^{  - \frac{5}{6} }  \times  {7}^{ -  \frac{7}{6} }  \\  =  {7}^{ -  \frac{5}{6} -  \frac{7}{6}  }  \\  =  {7}^{  -  \frac{12}{6} }  \\  = {7}^{ - 2}  \\  =  \frac{1}{ {7}^{2} } \\  =  \frac{1}{49}
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4 0
3 years ago
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In-s [12.5K]

Answer:

x = -5/2 + i√19 and x = -5/2 - i√19

Step-by-step explanation:

Next time, please share the possible answer choices.

Here we can actually find the roots, using the quadratic formula or some other approach.

a = 1, b = 5 and c = 11.  Then the discriminant is b^2-4ac, or 5^2-4(1)(11).  Since the discriminant is negative, the roots are complex.  The discriminant value is 25-44, or -19.

Thus, the roots of the given poly are:

      -5 plus or minus i√19

x = -----------------------------------

                     2(1)

or x = -5/2 + i√19 and x = -5/2 - i√19

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Answer:

g

Step-by-step explanation:

gg

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\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad &#10;radius=\stackrel{}{ r}\\\\&#10;-------------------------------\\\\&#10;(x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2}&#10;\\\\\\&#10;center~(3,-7)\qquad radius=8

so, the broadcast location and range is more or less like the picture below.

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3 years ago
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