There can't be more than seven $5 bills, because they would be worth $33.
So, let's try all other cases and see which fits the requests:
- If there are six $5 bills, they are worth $30. You need three more $1 bills to reach $33. So, you have a total of 9 bills, which is not what we want.
- If there are five $5 bills, they are worth $25. You need eight more $1 bills to reach $33. So, you have a total of 13 bills, which is not what we want.
- If there are four $5 bills, they are worth $20. You need thirteen more $1 bills to reach $33. So, you have a total of 17 bills, which is not what we want.
- If there are three $5 bills, they are worth $15. You need eighteen more $1 bills to reach $33. So, you have a total of 21 bills, which is not what we want.
- If there are two $5 bills, they are worth $10. You need twenty-three more $1 bills to reach $33. So, you have a total of 25 bills, which is not what we want.
- If there is one $5, it is worth $5. You need twenty-eight more $1 bills to reach $33. So, you have a total of 29 bills, which is not what we want.
So, there's no way you can have 31 bills worth $1 and $5 that are worth $33 in total.
Answer:
i can help
Step-by-step explanation:
Answer:
Answer is A.. ( i.e. 3x + 7 )
[9tan(θ) * 9cot(θ)] / 9sec(θ)
First cancel out the 9's:
tan(θ)cot(θ)/sec(θ)
Recall the following trig identities:
tan = sin/cos
cot = cos/sin
sec = 1/cos
Thus, we can rewrite the expression as:
[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))
In the numerator, the sine's and cosine's cancel each other out:
1 / (1/cos(θ))
which we can rewrite as cos(θ).
the rate of change of a linear function is the same slope
the slope of a linear function is the coefficient that accompanies the variable in this case the variable is x and the slope is -2
so, the rate of change for y is -2
