Answer:
3.07% probability that exactly 12 of 15 Indy race drivers survive a crash
Step-by-step explanation:
For each driver, there are only two possible outcomes. Either they survive a crash, or they do not. The probability of a driver surviving a crash is independent from other drivers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which ![C_{n,x}[\tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.[tex]C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%5B%5Ctex%5D%20is%20the%20number%20of%20different%20combinations%20of%20x%20objects%20from%20a%20set%20of%20n%20elements%2C%20given%20by%20the%20following%20formula.%3C%2Fp%3E%3Cp%3E%5Btex%5DC_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
95% of Indy race drivers will survive a crash.
This means that 
What is the probability that exactly 12 of 15 Indy race drivers survive a crash?
This is P(X = 12) when n = 15. So


3.07% probability that exactly 12 of 15 Indy race drivers survive a crash