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klasskru [66]
3 years ago
11

How do I solve this question?

Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

using algebraic formula (a^m)^n= a^{mn}

now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

x^{mn} = x^{6}

mn=6 ....(1)

now

y^{2m} = y^{4}

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

(2 x^{3} y^2)^2 = 4 x^6 y ^4\\

4 x^6 y^4 = 4 x^6 y^4

both are equating so m= 2 and n=3

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