Answer:
19.25ft
Step-by-step explanation:
area = length x width so 3.5 x 5.5 = 19.25
No, Brianna is not correct.
The distance around the pool is 131.4 ft
Step by step explanation:
1) Semi circle with a diameter equal to the side opposite it, 20 ft.
Find the length of half the circle:
Circumference of semi-circle = (1/2)(πd)
Where:
π = 3.14
d = 20 ft.
Circumference of semi-circle = (1/2)(3.14)(20 ft) = 31.4 ft.
2) Vertical lengths from the endpoint of semi-circle to the endpoints of horizontal lengths, 40 ft each ⇒ 2 × 40 ft. = 80 ft.
3.) Horizontal length at 20 ft.
Add the semi-circle, vertical, and horizontal lengths:
Distance around the pool = 31.4 ft + 80 ft. + 20 ft.
Distance around the pool = 131.4 ft.
Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
I wanna say the 6th one down
Answer:
4/6
Step-by-step explanation:
