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monitta
3 years ago
15

Paragraph to write to my girl?????

Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

You make me feel like I can do anything and I am so happy to be with you. Thank you for being the wonderful, amazing person that you are. You surprise me every day and you warm my heart every night. I am the person I am today because you've loved me and helped me, love.

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6. Use synthetic substitution to evaluate the polynomial P(x) = x - 4x² + 4x – 5 for x = 4
Tatiana [17]

Answer:

When x=4

P(x) =4 - 4(4)^2 + 4(4) -5

=4 - 4(16) + 16 -5

=4 - 64 +11

= -60 + 11

= -49

8 0
3 years ago
How many cm are in 84.363 km​
Studentka2010 [4]

Answer:

8,436,300 cm

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the table below to make a scatter plot of the data pairs (years since 1960, population) PLEASE HELP
Tpy6a [65]

Take 1960 as 0 then find out next year's

  • 1970=10
  • 1980=20
  • 1990=30
  • 2000=40
  • 2005=45
  • 2010=50

Also

Divide each population by one thousand i.e turn to decimal .

This we done to create the plot on graph easily

The graph has been attached

for the below points

  • (0,9.706)
  • (10,10.652)
  • (20,10.798)
  • (30,10.847)
  • (40,11.353)
  • (45,11.478)
  • (50,11.576)

7 0
2 years ago
Read 2 more answers
∠A and \angle B∠B are vertical angles. If m\angle A=(6x-11)^{\circ}∠A=(6x−11) ∘ and m\angle B=(5x+4)^{\circ}∠B=(5x+4) ∘ , then f
ICE Princess25 [194]

Answer: \angle B=79^{\circ}.

Step-by-step explanation:

When two lines cross each other , then the opposite angles are known  as vertical angles.

Vertical angles are equal.

Here, ∠A and ∠B are vertical angles.

So, ∠A = ∠B

If \angle A=(6x-11)^{\circ} and \angle B=(5x+4)^{\circ}

Then , 6x-11=5x+4

Subtract 5x from both sides, we get

x-11=4

Add 11 on both sides, we get

x=15

Now , \angle B=(5(15)+4)^{\circ}=79^{\circ}

Hence, the measure of \angle B=79^{\circ}.

3 0
3 years ago
a square poster of length 3x is going to have a square painting centered on it. The length of the painting is 2x. the area of th
eduard
One way to solve this is to look at the size of the poster, and then subtract the size of the picture so you have the area that needs to be painted left.

Area of square poster - 3x × 3x = 9x^2
Area of painting - 2x × 2x = 4x^2

9x^2 - 4x^2 = 5x^2

The area is 5x^2
3 0
4 years ago
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