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kicyunya [14]
3 years ago
9

Avery is learning how to type. She increases the number of words she can type in a minute by 15% every week. This week she can t

ype 25 words a minute. In 6 weeks about how many words a minute should she be able to type?
A) 40 words
B) 50 words
C) 58 words
D) 100 words
Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0

Answer:

C) 58

Step-by-step explanation:

Aleonysh [2.5K]3 years ago
4 0
This is exponential growth...

F=ar^t

F=25(1.15^t) so in six weeks...

F=25(1.15^6)

F≈57.82

F≈58 words per minute (to nearest whole word per minute)
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Determine the kinetic energy of a 100-kg roller coaster car that is moving with a speed of 20.0/ms.
rjkz [21]

Answer:

The kinetic energy is 20,000\ J

Step-by-step explanation:

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3 0
3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 &lt; 0&lt; 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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