Find the distance between the two points rounding to the nearest tenth (if necessary).
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Answer:
Step-by-step explanation:
Since the population standard deviation , is known, we use the z confidence interval for the mean.
This is given by:
For a 95% confidence interval we use .
It was also given that: ,
and
Let us substitute the values to get:
<u>Interpretation:</u>
We can say with 95% confidence that the interval between 1463.3 and 1580.7 SAT scores contains the population mean based on the sample 125 SAT scores.
The answer is 96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is 96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is 96%.