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maksim [4K]
3 years ago
9

Paul has $2,400 in a savings account earning 3.4% simple interest. How much more interest would he earn in 5 years if the intere

st were compounded annually?
Mathematics
1 answer:
bija089 [108]3 years ago
7 0
Amount using compound interest = 2400(1 + 0.034)^5 = 2400(1.034)^5 = 2400(1.1820) = $2,836.70

Amount using simple interest = 2400(1 + 5 x 0.034) = 2400(1 + 0.17) = 2400(1.17) = $2,808

Difference = $2,836.70 - $2,808 = $28.70

Therefore, <span>he will earn $28.70 more interest in 5 years if the interest were compounded annually</span> .
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Two adjacent supplementary angles are
denis-greek [22]

Answer:

∠BPZ and ∠APZ

Step-by-step explanation:

These two angles share a common side and their non common side lies on a straight line.

8 0
3 years ago
PLEASE HELP WITH EXPLANATION <br><br> F(x) = 3 - x; g(x) = -2x <br><br> find f(g(2))
ioda

Given,

f(x) = 3 - x

and

g(x) = -2x

Now,

g(2) =  - 2(2) =  - 4

f(g(2)) = 3 - ( - 4) = 3 + 4 = 7

8 0
2 years ago
james borrows Php 700000 and promises to pay the principal and interest at 15% compounded monthly. How much must he repay after
Licemer1 [7]

Answer:

A = $ 1,987,379.10 + 700,000= $2,687,379.10

Step-by-step explanation:

15% = 0.15 rate per tear

A = P (1+r/n)^nt

A = 700,000 (1+0.015/12)^12*7

A = 700,000 (1+0.0125)^84

A = 700,000 ((0.9875)^84

A = 700,000 (2.839113)

4 0
2 years ago
Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul
Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 4

Sample mean, \bar{x} = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4\\H_A: \mu \neq 4

We use two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0
3 years ago
Please help answer by putting <br> "question ___ is option ___"
Juliette [100K]

Answer:

B A C A B

Step-by-step explanation:

i took this test before

4 0
2 years ago
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