last one. i can do the first part. put x = distance from top of ladder to the floor, y = distance from base of ladder to the wall (draw a picture) then pythagoras sez
<span><span>x2</span>+<span>y2</span>=25</span>
calculus says
<span>2x<span>x′</span>+2y<span>y′</span>=0</span>
and you are told that
<span><span>y′</span>=2</span>
so you know
<span>2x<span>x′</span>+4y=0</span>
or
<span><span>x′</span>=−<span><span>2y</span>x</span></span>
Answer:
its 5 Obviously :)
Step-by-step explanation:
get it
Answer:
A, C, D and K
Step-by-step explanation:
Inequalities:
y ≤ −2x + 10 and y >1/2x-2
<u>Finding zeros for the first inequality:</u>
- x=0 ⇒ y= 10, point (0, 10)
- y=0 ⇒ x= 5, point (5, 0)
- Locating these 2 points and connecting to get the first line.
Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.
<u>Finding zeros for the second inequality:</u>
- x=0 ⇒ y= -2, point (0, -2)
- y= 0 ⇒ x= 4, point (4, 0)
- Locating these points and connecting to get the second line.
Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.
Now we have the space of intersection of the above inequalities.
So the points in same section are the solution.
They are:
See attached for explanation