The area of a rectangular patio is (12x - 4) square units. What are possible dimensions of the patio?

1 answer:

4 0

You need two terms that multiply to (12x-4). The term on the outside needs to be a common multiple of 12 and 4. The common factors are 1, 2, and 4. Here are the following possible dimensions:
1(12x-4)
2(6x-2)
4(3x-1)
Hope this helps.

You might be interested in

PLEASE HELP!! 99 PTS AND AWARDING BRAINLIEST!!!<3

Flauer [41]

I think the answer would be C
Because if you actually work that out the answer would be 1/625 as first you simplify what's inside the bracket then you raise the numerator and denominator to that power

7 0

3 years ago

Read 2 more answers

Find the x value for the point that divides the lines segment AB into ratio of 2:3

m_a_m_a [10]

Let $(x_A,y_A),\ (x_B,y_B)$ be the coordinates of the points A and B and $(x_0,y_0)$ be the coordinates of the point O that divides the segment AB in ratio 2:3.

Consider vectors

$\overrightarrow{AO}=(x_0-x_A,y_0-y_A),\\ \\\overrightarrow{OB}=(x_B-x_0,y_B-y_0).$

These vectors are collinear and

$\dfrac{\overrightarrow{AO}}{\overrightarrow{OB}}=\dfrac{2}{3}.$

Then

$\left\{\begin{array}{l}\dfrac{x_0-x_A}{x_B-x_0}=\dfrac{2}{3}\\ \\\dfrac{y_0-y_A}{y_B-y_0}=\dfrac{2}{3}\end{array}\right.\Rightarrow \left\{\begin{array}{l}3(x_0-x_A)=2(x_B-x_0)\\ \\3(y_0-y_A)=2(y_B-y_0)\end{array}\right..$

This means that

$\left\{\begin{array}{l}3x_0-3x_A=2x_B-2x_0\\ \\3y_0-3y_A=2y_B-2y_0\end{array}\right.\Rightarrow \left\{\begin{array}{l}5x_0=2x_B+3x_A\\ \\5y_0=2y_B+3y_A\end{array}\right..$