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3 years ago

One step equation for algebra 1 can someone help

Mathematics

2 answers:

Julli [10]3 years ago

4 0

15+m=34 -15. -15 M=19 N-12=-20 +12. +12 N=-8 V+16=8 -16. -16 V=-8 A-15=-5 +15. +15 A=10

Alinara [238K]3 years ago

4 0

2) m=19 4) n=−8 6) v=−8 8) a=10 Hopefully that helps you ❤

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Write the equation in slope intercept form when slope = 6/5 and the y- intercept =-8

Ratling [72]

Step-by-step explanation:

Exercícios:

9. Sobre o estudo de equações, escreva V para as afirmações verdadeiras e F para as falsas.

a) ( ) A expressão 17 - 4x + 25 representa uma equação.

b) ( ) O número 23 representa um dos membros da equação -9x + 4 = 23.

c) ( ) Na equação x + 4 = 3x + 20, a incógnita é x.

d) ( ) A equação 3y - 15 = 0 não tem segundo membro.

7 0

2 years ago

HELPPPPPPPP!!!!!!!!!!

Novosadov [1.4K]

Step-by-step explanation:

98 = 188t - 16t^2

-16t^2 + 188t = 98

-16t^2 + 188t - 98 = 0

8t^2 - 94t + 49 = 0

Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions

t = [(47 - root 1817) / 8]≈ 0.55

and

t = [(47 + root 1817) / 8] ≈ 11.20

8 0

3 years ago

The hour hand on a clock is 4 cm long, and the minute hand is 10 cm long. What is the exact distance between the tips of the han

Allushta [10]

Answer:

2 sqrt(19)

Step-by-step explanation:

We know that the angle between the two hands

360 /12 *2 = 60 degrees

We divide by 12 because there are 12 number and multiply by 2 because there are 2 number between 10 and 12

This is a triangle where we know 2 sides and the angle between them.

We can use the law of cosines to determine the third side

c^2 = a^2 + b^2 -2abcosC

Where C is the angle between sides a and b

a =4 and b = 10 C = 60 and we are looking for side c

c^2 = 4^2 + 10^2 -2*4*10 cos60

c^2 =16+100 - 80cos 60

c^2 = 76

Take the square root of each side

sqrt(c^2) = sqrt(76)

c = sqrt(76)

c =sqrt(4) sqrt(19)

c =2 sqrt(19)

4 0

3 years ago

Solve the equation by completing the square

Andrews [41]

Answer:

b1= $2\sqrt{46} +10$

b2= $10-2\sqrt{46}$

Step-by-step explanation:

4 0

3 years ago

Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he

Olegator [25]

Answer:

$1.90

Step-by-step explanation:

Represent the numbers of nickels, dimes and quarters by n, d and q.

Then: d + q = 9, or q = 9 - d.

Also, n + d = 10

Lastly, n + d + q = 15.

Let's substitute 9 - d for q in the equation immediately above:

n + d + (9 - d) = 15, or n + 9 = 15. Then n must be 6.

In summary, Jim has 6 nickels, (10 - 6) dimes and (9 - 4) quarters, or:

6 nickels, 4 dimes and 5 quarters

Thus, he has 5($0.05) + 4($0.10) + 5($0.25), or

$0.25 + $0.40 + $1.25, or $1.90

7 0

3 years ago