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Savatey [412]
3 years ago
13

2968 Divided. By. 56. What. Is the answer to this problem please show your work

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

53

Step-by-step explanation:

i had to use this old method (pic related).

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How many solutions does 9x+5=9x+7
Troyanec [42]

Answer:

There are 0 solutions to this problem because it cannot be re-arranged logically enough to come to a new conclusion.

3 0
2 years ago
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The current value Of a investment is 25% More than its initial value the increase in value is 10million what was the initial val
azamat

Answer:

50 million

Step-by-step explanation:

current value: c

initial value : i

c = 1.2 × i

x - i = 10

10 + i = 1.2 × i

0.2 ×i = 10

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8 0
3 years ago
Question in pic. please help!
bonufazy [111]

Answer: 1, 3, and 4 can form triangles. The rest can not.

Step-by-step explanation:

on triangles 1, 3, and 4, the 2 smaller sides added together are greater than the longer side.

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3 years ago
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Solve the exponential equation: 4x - 2 = 2x​
svetlana [45]

Answer:

x= 1

Step-by-step explanation:

Solve

Let's solve your equation step-by-step.

4x−2=2x

Step 1: Subtract 2x from both sides.

4x−2−2x=2x−2x

2x−2=0

Step 2: Add 2 to both sides.

2x−2+2=0+2

2x=2

Step 3: Divide both sides by 2.

2x

2

=

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8 0
3 years ago
what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
Dmitrij [34]
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
3 0
3 years ago
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