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Archy [21]
3 years ago
6

Slope and y intercept of 6x=4y-8 with work shown please

Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0

6x = 4y - 8

4y = 6x + 8

y = (3/2) x + 2

Answer: Slope 3/2, y intercept 2

inna [77]3 years ago
4 0

Answer:

slope= 3/2

y-intercept= 2

Step-by-step explanation:

6x=4y-8

1. move -8 to the opposite side then youll get

   

     4y=6x+8

2. now divide the 4 to all of the numbers and then u should get

     y=3/2x+2

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N/4 &lt; -1 on a number line<br> -10x&gt;-100 on a number line <br> 5x&gt;20 on a number line
blsea [12.9K]
N/4 < -1 — we can multiply both sides with 4, so we dont have to deal with fractions.

N < -4

So, our N goes left from -4 on a number line.

-10x<-100 — divide both sides by 10
-x < -10
x > 10

X is from 10 rightwards.

5x>20 — divide both sides by 5
x > 4

X is rightwards from 4.


4 0
3 years ago
Ashley bought some books. She spent a total of $58 after a discount of $8 off of her total purchase. Each book cost $6. How many
Artyom0805 [142]

Answer:

11 books

b=(58+8)/6

Step-by-step explanation:

58+8=66

66/6=11

11

6 0
3 years ago
Is half the sum of two and a number multiplied by itself three times linear? (and how would I write it as a mathematical express
castortr0y [4]
I’m not sure if it’s linear but u write it as 2 divided by 2 to the power of three
6 0
3 years ago
Use double integrals to calculate the area inside the ellipse whose semiaxes have length a and b
Stells [14]
The general equation of an ellipse centered at the origin with its semiaxes coinciding with the coordinate axes is given by

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

Substituting x=a\cos\theta and y=b\sin\theta into the above equation gives the Pythagorean identity, so we can use polar coordinates quite nicely to our advantage.

If \mathcal E is the ellipse with the equation above, the area is given by the double integral

\displaystyle\iint_{\mathcal E}\mathrm dA=\iint_{(x/a)^2+(y/b)^2\le1}\mathrm dx\,\mathrm dy

Let x(r,\theta)=ar\cos\theta and y(r,\theta)=br\sin\theta, so that the Jacobian matrix is

\mathbf J=\begin{bmatrix}x_r&x_\theta\\y_r&y_\theta\end{bmatrix}=\begin{bmatrix}a\cos t&-ar\sin t\\b\sin t&br\cos t\end{bmatrix}

and the magnitude of its determinant is |\det\mathbf J|=|abr|=abr

since in polar coordinates we use the convention that r\ge0, and a,b>0 because they are lengths.

Now, the area is given by

\displaystyle\iint_{\mathcal E}\mathrm dA=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}abr\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi a b\int_{r=0}^{r=1}r\,\mathrm dr
=\pi a b
4 0
4 years ago
Identify a pair of same-side interior angles
-Dominant- [34]

Answer:

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Step-by-step explanation:

???

7 0
3 years ago
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