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3 years ago

Please help i will mark you five stars and give you 20 points

Mathematics

2 answers:

Virty [35]3 years ago

6 0

That would be a reflection

Gnom [1K]3 years ago

5 0

Answer:

Reflection

Step-by-step explanation:

You might be interested in

Round 7.2352297363 to nearest millionth

Elodia [21]

Answer:

7.23522974

Step-by-step explanation

7 would be in the ones place, 2 in the tenths, 3 in the hundredth, 5 in the thousandth, and so on. Since the number after 3 is over 5, it will go up by one. So the answer would be 7.23522974

6 0

3 years ago

Read 2 more answers

How can you use a quick picture to find 3x2.7

NeTakaya

If you mean like a method to solve it fast here I have 1 solution I usually use;

3x2.7
3x.7=2.1
3x2=6
Then in the question there is 1 number behind the decimal point so the answer should have 1 number behind as well.
=8.1

3 0

4 years ago

Read 2 more answers

The linear function y=2x+28 models the average cost of a haircut in a certain city, where y, is the average price of a haircut x

Zepler [3.9K]

Answer:

The slope of the model is $m = 2\,\frac{USD}{yr}$ .

The value of the slope indicates that the average cost of a hair cut is increased by 2 US dollars each year.

Step-by-step explanation:

We have to notice that given function is a linear function, that is, a first order polynomial, whose standard form is described below:

$y =m\cdot x + b$

Where:

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

In this case, we use the linear function $y = 2\cdot x + 28$ , where $x$ is the time after 2000, measured in years, and $y$ is the average cost of a hair cut. The slope of the model is $m = 2\,\frac{USD}{yr}$ .

The value of the slope indicates that the average cost of a hair cut is increased by 2 US dollars each year.

8 0

4 years ago

One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt

mash [69]

Answer: $864\ m^2,\ 24\ m$

Step-by-step explanation:

Given

Perimeter of the rhombus is $120\ m$

Length of one of the diagonal is $d_1=36\ m$

All the sides of the rhombus are equal

$\Rightarrow 4a=120\\\Rightarrow a=30\ m$

Area of the rhombus with side and one diagonal is

$\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}$

Insert the values

$\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2$