Where is 10/3 pi on the unit circle?

Please Help With all 3! Will Give 100 Points + Brainliest!

koban [17]

Answer: I don't see anything. Maybe upload some images?

Step-by-step explanation:

3 0

3 years ago

Simplify 1)5x+3=x+13 2)5/2x-1/X =1/6

Artyom0805 [142]

Step-by-step explanation (Question 1):

Step 1: (Question 1): Subtract x from both sides.

5x+3=x+13

5x+3−x=x+13−x

4x+3=13

Step 2: (Question 1): Subtract 3 from both sides.

4x+3−3=13−3

4x=10

Step 3: (Question 1): Divide both sides by 4.

4x/4 = 10/4

FIRST ANSWER: x = 5/2

Step-by-step explanation (Question 2):

Step 1: (Question 2): Multiply by LCM

15x^2 - 6 = x

Step 2: (Question 2): Solve 15x^2

15x^2 - 6 = x:

x = 2/3

x = -3/5

Step 3: (Question 2): Solve

ANSWER: x=0.666667 or x=−0.6

See Attachment 1 for question 1 steps (FULL)

See Attachment 2 for question 2 steps (FULL)

Answer:

1) x = 5/2

2) x=0.666667 or x=−0.6

Hope this helps.

8 0

2 years ago

Read 2 more answers

Amy was scheduled for 12 intervals this week. One her first interval, she had a technical issue that prevented her from working

ad-work [718]

Based on the total of intervals vs the number of intervals Amy attended her CA percentage is 75%

<h3>What is the CA percentage?</h3>

The CA percentage measures the commitment of an employee to be logged in during the intervals that were assigned to him/her to work.

In this way, the CA percentage is equal to 100% if the employee worked as scheduled. Moreover, this percentage can be affected by factors such as:

Technical issues.
Human errors.

In the case of Amy, there is a total of 12 intervals and it is known:

She had a technical issue that prevented her from working, but this was reported so it is unlikely this is considered in her CA.
She missed three intervals because she looked at her schedule wrong.

Based on this information, let's calculate her CA:

12 intervals = 100%
9 intervals = x

x = 9 x 100 / 12
x = 900 / 12
x = 75%

Learn more about percentage in: brainly.com/question/8011401

6 0

3 years ago

The number of bacteria in a second study is modeled by the function b_2(t)=800(1.6)^t.

Lisa [10]

Answer:

1.6 = 1 + .6 = 60% growth rate

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

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Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

2 years ago