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balu736 [363]
4 years ago
12

What is the radius of an ellipse

Mathematics
1 answer:
zheka24 [161]4 years ago
3 0

Answer:

Finding the radius of an ellipse is more than just a single simple operation; it's two simple operations. The radius is the line from the center of an object to its perimeter. An ellipse, which is like a circle that has been elongated in one direction, has two radii: a longer one, the semimajor axis, and a shorter one, the semiminor axis. These two radii are calculated using the focal points, which are two points that are equidistant of the ellipse's center, and a point on the ellipse’s perimeter.

Measure the distance in between the two focal points and then square it. For this example, the distance between the focal points, or foci, is 6. The square of 6 is 36.

Measure the distance of the point on the perimeter from each of the foci. For this example, the point is 4 from one focal point and 6 from the other. brainliest?

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Answer:

  about 5.84 mg

Step-by-step explanation:

The amount remaining after t days can be written as ...

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3 years ago
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Answer:

the \: floor \: has \: the \: following \: dimensions \to \\ \boxed{ length \: of \: 37.35 \: meters} \\ and \\  \boxed{width \: of \: 5.35 \: meters}

Step-by-step explanation:

let \: the \: width \: of \: the \: floor \: be \to \: w \\ let \: the \: length \: of \: the \: floor \: be \to \: l = w + 32 \\ but  \: the\: are a\: of \: the \: rectangular \: floor \: is \to \\ a = lw = 200 \\ w(w + 32) = 200 \\  {w}^{2}  + 32w   = 200 \\ {w}^{2}  + 32w    - 200 = 0 \\ w =  \frac{ - 32 +  \sqrt{32 {}^{2} - 4(1)( - 200) } }{2(1)}  \\ \boxed{ w = 5.35} \\ hence \\ l = 5.35 + 32  \\  \boxed{l= 37.35}

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