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hoa [83]
3 years ago
10

PLEASEEEE HELPPP!! 30 POINTS! PROVE THAT AM IS PERPENDICULAR TO BM

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Extend the line segment AM until it touches AC, and call that intersection point P. Triangle AMP then forms a pair of similar triangles:

\Delta AMP\sim\Delta PDM

From this we know that angles MDP and AMP are congruent, and we already know MDP is a right angle so it follows that AM\perp BM.

(You can ignore most of the labels in the image; I realized moments later after posting that the proof is much simpler than I originally thought)

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Andrews [41]

Answer:

(2x+1)(x+3)

Step-by-step explanation:

Not much explaining for that...

7 0
4 years ago
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In the equation y=mx+b, what does the x stand for? And, in the equation y=3x+6 how would I solve for y?
ladessa [460]

Answer:

x stays x in both equations so x stands for x

Step-by-step explanation:

y=3x+6

you can put this into a graphing caculator or draw it yourself.

6 is the y value when x equals 0. and the 3 represents the slope so then it is solved for any y value

7 0
3 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
Mario took clothes to the cleaners three times last month. first, he brought 3 shorts and 1pair of slacks and $10.96. then, he b
valina [46]

Let us say that:

x = cost of shorts

y = cost of slacks

z = cost of sports coat

 

From the given statements, we can create the following equations:

eqtn 1: 3 x + y = 10.96

eqtn 2:  7 x + 2 y + z = 30.40

eqtn 3:  4 x + z = 14.45

 

Rewrite eqtn 1 explicit to y:

y = 10.96 – 3 x                    --> eqtn 4

 

Rewrite eqtn 3 explicit to z:

z = 14.45 – 4x                     --> eqtn 5

 

Plug in the values of y (eqtn 4) and z (eqtn 5) to eqtn 2:

7 x + 2 (10.96 – 3 x) + 14.45 – 4 x = 30.40

7 x + 21.92 – 6 x + 14.45 – 4 x = 30.40

- 3 x + 36.37 = 30.40

- 3 x = - 5.97

x = 1.99

 

Eqtn 4:

y = 10.96 – 3 x   

y = 10.96 – 3 (1.99)

y = 4.99

 

Eqtn 5:

z = 14.45 – 4x

z = 14.45 – 4 (1.99)

z = 6.49

 

 

Therefore each shirt cost $1.99, each slacks cost $4.99, and each sports coat cost $6.49.

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7 0
4 years ago
Select the two values of x that are roots of this equation.<br> 2x-5=-3x2
anygoal [31]

Answer:

Step-by-step explanation:

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