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Harman [31]
3 years ago
6

Help Plis.......................

Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Two negative signs make a positive number. So -(-4) makes 4. I know it sounds weird, but thats what schools teach. Hope this helps!

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Given two central angles in any two circles, the ratio of the arc length to the radius of each corresponding circle is equal if
krok68 [10]
First, we have
s1/r1 = s2/r2

The question also states the fact that
s/2πr = θ/360°

Rearranging the second equation, we have 
s/r = 2πθ/360°

Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°

which is now 
2πθ1/360° = 2πθ2/360°

By equating both sides, 2π and 360° will be cancelled, therefore leaving 
θ1 = θ2
6 0
3 years ago
Need help asap! Show work if you can, it’s completely ok if you don’t tho
Savatey [412]
Its A) -67
plug the m and n values into the function and solve using pemdas.
5(-7)-2(-7+3)^2
-35-2(-4)^2
-35-2(16)
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-67
8 0
3 years ago
HELP ME ASAP FOR BRANETEST I MEAN IT >_
Julli [10]

Answer:1 1/6

Step-by-step explanation:

7 0
3 years ago
Rachel charges $7 to rake leaves in her neighborhood.Last week,she raked leaves in 3 yards.She put 2/3 of her savings account.Ho
Phantasy [73]

Answer:

14

Step-by-step explanation:

7*3=21

2/3 of 21 is 14 so she saved 14 dollars

6 0
3 years ago
Read 2 more answers
The coordinate plane shows the positions of different places in a town. Each unit on the graph is equal to 1 block. Match the pa
Karolina [17]

Home is located at the point (-5, 5)

The park is located at the point (-2, 3)

Apply the distance formula

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-5-(-2))^2 + (5-3)^2}\\\\d = \sqrt{(-5+2)^2 + (5-3)^2}\\\\d = \sqrt{(-3)^2 + (2)^2}\\\\d = \sqrt{9 + 4}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\

When rounding to the nearest whole number, we get 4. This is the approximate distance (in blocks) from home to the park. I'm not sure why "4 blocks" isn't listed as a possible distance, so there may be a typo somewhere.

You'll apply this idea to the other pairs of points to find the other distances.

8 0
2 years ago
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