We have a "rectangular" double loop, meaning that both loops go to completion.
So there are 3*4=12 executions of t:=t+ij.
Assuming two operatiions per execution of the innermost loop, (i.e. ignoring the implied additions in increment of subscripts), we have 12*2=24 operations in all.
Here the number of operations (+ or *) is exactly known (=24).
Big-O estimates are used for cases with a varying scale of operations, governed by a variable (usually n) to indicate the sensitivity of the number of operations relative to a change in the size of n.
Here we do not have a scale, nor n is defined. The number of operations is constant and known at 24. So a variable is required to find the big-O estimate.
Answer:
it's the last one *25,000 J
Step-by-step explanation:
Answer:
482.7972612 cm. Just round from here.
Step-by-step explanation:
Ah, the sine law questions. Ok so you know 
. If you don't, voila. Obviously, the variables are different but we can use the same formula. So, we have
Plug in:
The answer when solving for x is the above
To find the volume of each prism, you will multiply the length by the width by the height.
V = lwh
3 3/4 x 3 x 3 1/4
V = 36 9/16 cubic feet
V = lwh
1/4 x 1/4 x 1/4
V= 1/64 cubic feet
Both boxes are similar in that they can be described as a rectangular prism.
They are different because one prism has congruent edges, so we call it a cube. The other one has varying side lengths, therefore it is only a rectangular prism.
