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Ipatiy [6.2K]
3 years ago
12

What are the domain and the range of this function?

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

<em>Domain: [-5,1)</em>

<em>Range: [-4,7)</em>

Step-by-step explanation:

<u>Domain and Range</u>

The graph shows a straight line that represents a function whose domain and range we are to determine.

To find the domain of a function given its graph we draw imaginary vertical lines from -∞ to +∞. The values of x where the line meets the graph belong to the domain.

We can find the domain of the function is [-5,1). Note the left endpoint is included because there is a solid dot and the right endpoint is not because the dot is hollow.

Similarly, the range can be determined by using horizontal lines. We can see such lines meet the graph in values of y ranging from -4 to 7. The latter not included. Thus, the range is [-4,7)

Domain: [-5,1)

Range: [-4,7)

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A marketing study was conducted to compare the mean age of male and femlae purchasers of a certain product. random and independe
notka56 [123]

Answer:

A. t ≥ 1.734

Step-by-step explanation:

Data given and notation  

\bar X_{m}=39.80 represent the mean for the sample male

\bar X_{f}=50.30 represent the mean for the sample female

s_{m}=10.040 represent the sample standard deviation for the males  

s_{f}=13.215 represent the sample standard deviation for the females  

n_{m}=10 sample size for the group male  

n_{f}=10 sample size for the group female  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for females is higher than the mean for males, the system of hypothesis would be:  

Null hypothesis:\mu_{f}-\mu_{m}\leq 0  

Alternative hypothesis:\mu_{f} - \mu_{m}> 0  

We don't have the population standard deviation, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{f}-\bar X_{m})-\Delta}{\sqrt{\frac{s^2_{f}}{n_{f}}+\frac{\sigma^2_{m}}{n_{m}}}} (1)

And the degrees of freedom are given by df=n_m +n_f -2=10+10-2=18  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

What is the test statistic?

With the info given we can replace in formula (1) like this:  

t=\frac{(50.3-39.80)-0}{\sqrt{\frac{13.215^2}{10}+\frac{10.040^2}{16}}}}=2.001

Critical value

For this case since we have a right tailed test we need to look into the t distribution with 18 degrees of freedom a value that accumulates 0.05 of the area on the right, and on this case:

t_{crit}=1.734

And the rejection zone of the null hypothesis would be: A. t ≥ 1.734

For our case our calculated value is higher than the critical value so we have enough evidence to reject the null hypothesis at the 5% of significance.

8 0
4 years ago
Scientists are studying a bacteria sample. The function f of x equals 256. 1.15 to the x. gives the number of bacteria in the sa
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Answer:

the number of bacteria increases at a rate of 15% each day

Step-by-step explanation:

Given the function :

f(x) = 256(1.15)^x

The function represents an exponential growth function ; comparing the equation with the general form of an exponential growth function :

f(x) = A(1 + r)^t

A = the initial value of the population, = 256

(1 + r),; r = growth rate

Therefore, to solve for r ;

1 + r = 1.15

r = 1.15 - 1 ; r = 0.15

Hence, growth rate = 0.15 = 0.15 * 100% = 15%

Hence, the number of bacteria increases at a rate of 15% each day

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Answer:

c

Step-by-step explanation:

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the rate of increase of the bush every month is 6 cm

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because the bush increases every month, 6x would be added to 30cm

y = 6x + 30

If the bush decreased at a rate of 6cm every month, the equation would be y = 30 - 6x

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M1-(17x+1) and m2(20x-14) find m2
Vadim26 [7]

Answer:

If your goal is to simplify it, then it would be

38Fmnsxi

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