Answer:
it would be -18
Step-by-step explanation:
because you would divide 108 by 6 and you will get -18 each second
Answer: The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . The upper and lower quartiles can be used to find another measure of variation call the interquartile range . The interquartile range or IQR is the range of the middle half of a set of data.
Step-by-step explanation:
Answer:
1.0
Step-by-step explanation:
The 6 is bigger than 5, so that bups the number up to 1.0.
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is 4x²
Answer:
b
Step-by-step explanation:
centroid
x=(x1+x2+x3)/3=(0+3+0)/3=3/3=1
y=(y1+y2+y3)/3=(0+0-3)/3=-3/3=-1
centroid =(1,-1)