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fredd [130]
3 years ago
13

Please help me with the problem

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

See the attachment.

Step-by-step explanation:

The approach is to take advantage of the definition of a perpendicular bisector to show the base lengths and right angles are congruent, then use SAS with the second side being CD (congruent to itself). It's mainly a matter of deciding what the various reasons are called.

It seems the goal is to show that AC = BC as marked.

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Factorise: a squared +8a -20
Vaselesa [24]
Factor out the 4 in both equations
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therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))


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3 years ago
6.25% tax on a $25 purse
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Step-by-step explanation:

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Given:

It is given that,

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the value of ∠QPR.

Formula

As per the given problem PR lies between PQ and PS,

So,

∠QPR+∠RPS = 90°

Now,

Putting the values of ∠RPS and ∠QPR we get,

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 in ∠QPR we get,

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

Hence,

The value of ∠QPR is 40°.

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

4 squares make up a triangle so divide the degrees if the square by the triangle.

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