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3 years ago

Please help me with the problem

Mathematics

1 answer:

katrin2010 [14]3 years ago

3 0

Answer:

See the attachment.

Step-by-step explanation:

The approach is to take advantage of the definition of a perpendicular bisector to show the base lengths and right angles are congruent, then use SAS with the second side being CD (congruent to itself). It's mainly a matter of deciding what the various reasons are called.

It seems the goal is to show that AC = BC as marked.

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Ms Rochelle wants to put her 29 students into 6 groups

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She needs 4 groups at the most, having 6 kids leftover, 6×4=24, not that hard

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3 years ago

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If 59% was 2687 what is 29% of the unmentioned number?

wariber [46]

Answer:

2687

2687×100/59=4554.2

29×4554.2/100= 2686.97 aprox. 2687

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3 years ago

The cost in dollars of making x items is given by the function C(x)=10x+900 .

Stella [2.4K]

For the given cost equation we have:

a) Fixed cost is $900.

b) For making 25 items the cost is $1150.

c) D: x ∈ [0, 150]

R: c ∈ [900, 2400]

<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

c(0) = 10*0 + 900 = 900

The fixed cost is 900.

b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.

c(25) = 10*25 + 900 = 250 + 900 = 1150

c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:

c( x₀) = 2400 = 10*x₀ + 900

Solving for x₀ we get:

x₀ = (2400 - 900)/10 = 150

Now we want to get the range and domain.

We know that we can make between 0 and 150 items, so the domain is:

D: x ∈ [0, 150]

For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:

R: c ∈ [900, 2400]

If you want to learn more about domain and range:

brainly.com/question/10197594

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5 0

2 years ago

Pls help ;-;

anyanavicka [17]

Answer:

Step-by-step explanation:

A closed circle means inclusive, and -2 is included in values that would make the equation true. Then you just have to test another number greater than and less than -2 to see which way the arrow should point.

-3(-3) + 1 < 7

9 + 1 < 7

10 < 7 FALSE

-3(0) + 1 < 7

1 < 7 TRUE

All values (including -2) will make this equation true

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3 years ago

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meriva

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