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2 years ago

Please help me with the problem

Mathematics

1 answer:

katrin2010 [14]2 years ago

3 0

Answer:

See the attachment.

Step-by-step explanation:

The approach is to take advantage of the definition of a perpendicular bisector to show the base lengths and right angles are congruent, then use SAS with the second side being CD (congruent to itself). It's mainly a matter of deciding what the various reasons are called.

It seems the goal is to show that AC = BC as marked.

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Which relation is a function?

Brums [2.3K]

The second relation is a function.

For a relation to be a function, each x-value can only have a singular corresponding y-value. Since all other relations feature x-values with multiple y-values, the second relation is a function.

5 0

2 years ago

PLZ HELP ASAP!!! I WILL NAME BRAINLIEST!! 65 POINTS!! (:

astra-53 [7]

Answer:

1. 44 + 3x

2. 2y - 8

3. x - 6

15. $5\frac{7}{8}$

16. $6\frac{1}{3}$

17. $3\frac{7}{9}$

Step-by-step explanation:

1. 7² + 2² - 5 - 4 + 3x

49 + 4 - 5 - 4 + 3x

53 - 5 - 4 + 3x

48 - 4 + 3x

44 + 3x

2. - y - 5 + y + 2(2y-y) - 3

-y - 5 + y + 4y - 2y -3

-y - 5 + 5y - 2y - 3

4y - 2y - 5 - 3

2y - 8

3. 5x -3 - x - 3(x + 1²)

5x - 3 - x - 3x - 3

4x - 3x - 3 -3

x - 3 -3

x - 6

15. $7\frac{1}{4} - 1\frac{3}{8}$

= $7 \frac{2}{8} - 1\frac{3}{8}$

= $\frac{58}{8} - \frac{11}{8}$

= $\frac{47}{8}$ → $5\frac{7}{8}$

16. $9 - 2\frac{2}{3}$

= $\frac{54}{6} - 2\frac{4}{6}$

= $\frac{54}{6} - \frac{16}{6}$

= $\frac{38}{6}$ → $6\frac{2}{6}$ → $6\frac{1}{3}$

17. $10\frac{1}{3} - 6\frac{5}{9}$

= $10 \frac{3}{9} - 6\frac{5}{9}$

= $\frac{93}{9} - \frac{59}{9}$

= $\frac{34}{9}$ → $3\frac{7}{9}$

Hope this helps.

6 0

3 years ago

2x-3y=3 5x+2y=17<br> how do i solve this?

Alina [70]

<span> 2(2x-3y=3)..................4x-6y=6..........equation 1
3(5x+2y=17) ...........15x+6y=51</span>........equation 2

adding equation 1 and equation 2;
19x=57
x=3

2x-3y=3
(2*3)-3y=3
6-3=3y
y=1

6 0

3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ?

Alja [10]

Using the factor theorem, it is found that the polynomial is:

$f(x) = x^3 - 2x^2 - 3x + 6$

Given by the first option

---------------------------

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ using the factor theorem it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.