Please help me with the problem
1 answer:
Answer:
See the attachment.
Step-by-step explanation:
The approach is to take advantage of the definition of a perpendicular bisector to show the base lengths and right angles are congruent, then use SAS with the second side being CD (congruent to itself). It's mainly a matter of deciding what the various reasons are called.
It seems the goal is to show that AC = BC as marked.
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Well, sine is 
,
but from the angle C, the opposite side, the one facing it off, is the side
AB, and we dunno what the side AB is
however, we know the hypotenuse is 8, and the adjacent side is 7,
and is right-triangle, thus, let us use the pythagorean theorem,
now, that we know what the opposite side is, that is AB, then
we can find the sine of angle C
but from the angle C, the opposite side, the one facing it off, is the side
AB, and we dunno what the side AB is
however, we know the hypotenuse is 8, and the adjacent side is 7,
and is right-triangle, thus, let us use the pythagorean theorem,
now, that we know what the opposite side is, that is AB, then
we can find the sine of angle C