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marusya05 [52]
3 years ago
9

14) Bennie bought some Snickers bars for $1.79 each. He also

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

15

Step-by-step explanation:

1. Subtract $6.59 from $33.44

2. Divide $26.85 (the answer to the first step) by 1.79

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3 years ago
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you are helping to organize a soccer tournament by registering the participating teams. each week 666 teams register to particip
algol13

The graph that best represent the relationship between time and cost is option A as it is a proportional graph

<h3>How to know the graph that represent the relationship between time and number of team?</h3>

Each week 6 teams register to participate.

Therefore, for every week 6 team register to participate in the competition.

This simply implies as time increases , the number of participant in the competition also increase.

Therefore, the equation that can be use to represent this situation is as follows:

y = 6x

where

  • y = number of team registered
  • x = time in weeks.

Hence,  the graph that best represent the relationship between time and cost is option A as it is a proportional graph. The registered team increases as the time in weeks increase.

learn more on graph relationship here: brainly.com/question/12812258

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2 years ago
Product of squre of x and cube of y
julsineya [31]

Answer:

x²y³

Step-by-step explanation:

(x²) (y³) = x²y³

Hope it helps!

Have a nice day:)

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2 years ago
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find an equation for the nth term of the sequence. -3, -12, -48, -192, ... select one: a. an = 4 • -3n 1 b. an = -3 • 4n - 1 c.
Andrews [41]
-3;-12;-48;-192;...\\\\It's\ the\ geometric\ sequence:a_n=a_1r^{n-1}\\\\a_1=-3;\ a_2=-12\\\\r=a_2:a_1\to r=-12:(-3)=4\\\\\boxed{a_n=-3\cdot4^{n-1}}\to\fbox{b.}
3 0
3 years ago
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Elisabeth ate 50g of a 60% chocolate bar and Sam ate 75g of a 40% chocolate bar. Who ate more chocolate
strojnjashka [21]

Answer:

elisabeth

Step-by-step explanation:

she has more of a percdntage of the chocalate bar taken away. whil only sam has 75 grams eaten elizabeth has a more percentage.

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