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coldgirl [10]
4 years ago
14

Combine the like terms to create an equivalen -k + 3k Stuck? Watch a video or use a hint.

Mathematics
1 answer:
viktelen [127]4 years ago
8 0

Answer:

2k

Step-by-step explanation:

-k+3k=3k-k=2k

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What are the numerical measures of each angle in the diagram? 1 and 3 measure degrees. 2 and 4 measure degrees. (3x - 1)º (2x +
Tanya [424]

Answer:

Step-by-step explanation:

In the diagram shown, the measure of angle 1 is oppositely directed to angle 2 and oppositely directed angles are equal.

Hence <1 = <3

Given < 1 = 3x-1 and <3 = 2x+9

Hence 3x-1 =  2x+9

collect like terms

3x-2x = 9+1

x = 10°

Since <1 = 3x-1

on substituting x = 10

<1 = 3(10)-1

<1 = 30-1

<1 = 29°

<1+<2 = 180 (angle on a straight line)

29+<2 = 180

<2 = 180-29

<2 = 151°

Similarly, on substituting x = 10 into <3

<3 = 2x+9

<3 = 2(10)+9

<3 = 20+9

<3 = 29°

<3+<4 = 180 (angle on a straight line)

29+<4 = 180

<4 = 180-29

<4 = 151°

3 0
3 years ago
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Amy rode her bike 180 miles in 6 days, how many miles did she ride in a DAY?
Ipatiy [6.2K]
30. You’d do 180 divided by 6 :)
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3 years ago
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A ball is projected in to the air. Its height at time t is given by the equation
Ksju [112]
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

h=-16 t^{2} +60t+1
8=-16 t^{2} +60t+1
16 t^{2} -60t-1+8=0
16 t^{2} -60t+7=0

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) t^{2} = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}
t= \frac{60plus minus \sqrt{3600-448 } }{32}
t= \frac{60plus minus \sqrt{3152 } }{32}

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
t=  \frac{60+56.1426}{32} =3.63
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t=  \frac{60-56.1426}{32} =.12

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.


3 0
3 years ago
The length of the hypotenuse of a right triangle is 14 inches. If the length of one leg is 6 inches, what is the approximate len
Liula [17]
Using the Pythagorean theorem:

6^2 + X^2 = 14^2

36 + x^2 = 196

X^2 = 196-36 

x^2 = 160

x = SQRT(160)

x = 4 SQRT(10)   
Or as a decimal:
x = 12.65 inches
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3 years ago
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Which properties of logarithms help you simplify log 200 + log 5 - log 100? (Select all that apply.)
bearhunter [10]

Answer:quotient property

Product property

Step-by-step explanation:

Just took the test

5 0
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