Given:
The equation of line is

To find:
The x and y-intercept of the given line.
Solution:
We have,

Putting x=0, we get

Add 6 on both sides.


Divide both sides by 4.

So, the y-intercept is
.
Putting y=0 in given equation, we get

Add 5 on both sides.


Divide both sides by 7.

So, the x-intercept is
.
Answer:
Step-by-step explanation:
d=m+a/n
Firstly, we multiply n to get rid of it by both sides. Since n is dividing a.
d=m+a/n
*n *n
dn=m+a
-m -m
a=dn-m
The tangent to
at the point (0, 5) has a slope equal to the derivative evaluated at
.

This tangent passes through the point (0, 5), so its equation is

The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is
