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pickupchik [31]
3 years ago
10

Divide 90kg into the ration 2:3:7

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
3 0

the answer would have to be 465

nekit [7.7K]3 years ago
3 0

Answer:

Weight of a pile of sand = 90 Kg

Ratio of weight of sand in three bags =

2 : 3 : 7

Let the weights be 2x kg, 3x kg and 7x kg respectively

A.T.Q.

=> 2x + 3x + 7x = 90

=> 12x = 90

=> x = 90/12

=> x = 7.5 Kg

___________________________

Weight of sand in small bag =

=> 2 × 7.5

=> 15 Kg ANS

Weight of sand in medium bag =

=> 3 × 7.5

=> 22.5 Kg ANS

Weight of sand in large bag =

=> 7 × 7.5

=> 52.5 Kg ANS

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Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that P(A) = 0.8, P(B) = 0.6

The probability that at least one part works for one year is 0.9.

This means that: P(A \cup B) = 0.9

We also have that:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

0.9 = 0.8+0.6 - P(A \cap B)

P(A \cap B) = 0.5

Calculate the probability that part B works for one year, given that part A works for one year.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

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Add 1 to both sides:

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Under this assumption, we square both sides and we have

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