I am assuming this is a triangle.....P = a + b + c
P = 2a - 3 + 2a + 3a + 1....combine like terms
P = 7a - 2 <==
I think i only get some of it. this is what i did
x = -3 to 4y = 0.3 to 3if we use -3 and 3a < -1 < b
a= -2 to infiniteb= 0 to infinite
Answer: x^2 + y^2 -10y = 0
Step-by-step explanation:
Cartesian coordinates, also called the Rectangular coordinates, isdefined in terms of x and y. So, for the problem θ has to be eliminated or converted using basic foundations that are described by the unit circle and the right triangle trigonometry.
r= 10sin(θ)
Remember that:
x= r × cos(θ)
y= r × sin(θ)
r^2= x^2 + y^2
Multiply both sides of the equation by r. This will give:
r × r = 10r × sin(θ)
r^2 = 10r × sin(θ)
x^2 + y^2= 10r × sin(θ)
Because y= r × sin(θ), we can make a substitution. This will be:
x^2 + y^2= 10y
x^2 + y^2 -10y = 0
The above equation is the Rectangular coordinate equivalent to the given equation.
Number 3: x+x+100= 180 x=40
number 4: x+x+112=180 x= 34
