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3 years ago

Joel is mailing a large envelope to his cousin. The envelope has pictures inside, so he doesn't want to bend it.

Mathematics

1 answer:

Nuetrik [128]3 years ago

8 0

Answer: Put a cardboard piece inside the envelope then mail it

Step-by-step explanation: If you make the cardboard piece the exact size as the pictures then put it behind all of the pictures it would make it hard for the pictures to bend if it has support.

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Pls help I This is geometry Been struggling due soon show work

yawa3891 [41]

Triangles have $180^{\circ}$ in total, so the sum of all the angles should be $180^{\circ}$

First triangle

$180 = 90 + (x + 5) + (2x - 2)\\180 = 90 + x + 5 + 2x - 2\\180 - 90 - 5 + 2 = x + 2x\\87 = 3x\\x = 29^{\circ}$

Second triangle

$180 = (x + 40) + (2x - 5) + (3x - 17)\\180 = x + 40 + 2x - 5 + 3x - 17\\180 - 40 + 5 + 17 = x + 2x + 3x\\162 = 6x\\x = 27^{\circ}$

3 0

4 years ago

Read 2 more answers

PLEASE HELP THANK YOU

Kazeer [188]

I think it should be 56%

5 0

4 years ago

The sum of 25 and x is 48 find x. . Solve.

ahrayia [7]

Answer:

x = 23

Step-by-step explanation:

Sum of 25 and x = 48

25 + x = 48

Subtract 25 from both sides

25 - 25 cancels out

48 - 25 = 23

We would be left with x = 23

5 0

3 years ago

Read 2 more answers

Question

Kay [80]

Answer:

$f(x)=2(x-2)(x^2+64)$

Step-by-step explanation:

A standard polynomial in factored form is given by:

$f(x)=a(x-p)(x-q)...$

Where p and q are the zeros.

We want to find a third-degree polynomial with zeros x = 2 and x = -8i and equals 320 when x = 4.

First, by the Complex Root Theorem, if x = -8i is a root, then x = 8i must also be a root.

Therefore, we acquire:

$f(x)=a(x-(2))(x-(-8i))(x-(8i))$

Simplify:

$f(x)=a(x-2)(x+8i)(x-8i)$

Expand the second and third factors:

$=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64$

Hence, our function is now:

$f(x)=a(x-2)(x^2+64)$

It equals 320 when x = 4. Therefore:

$320=a(4-2)(4^2+64)$

Solve for a. Evaluate:

$320=(2)(80)a$

So:

$320=160a\Rightarrow a=2$

Our third-degree polynomial equation is:

$f(x)=2(x-2)(x^2+64)$

7 0

3 years ago

Find an equation of a plane through the point (3, 0, 2) which is orthogonal to the linex=?2+3t,y=2+4t,z=?1?3tin which the coeffi

Alchen [17]

Answer: 3x + 4y - 3z - 3 = 0

Step-by-step explanation:

with the given point (3, 0, 2), the plane is orthogonal to this line so it

has directional ratios (3, 4, -3)

therefore the given equation can be written as;

(x+2)/3 = (y-2)/4 = (z+1)/-3

so equation of the plane passing through point x1, y1 and z1 in the one point form is given as;

a(x-x1) + b(y - y1) + c(z -z1) = 0

abc represent the direction ratio

so we substitute

3(x-3) + 4(y-0) + (-3(z-2)) = 0

3x - 9 + 4y - 0 - 3z + 6 = 0

3x + 4y - 3z - 3 = 0

therefore the equation of the plane through the point is 3x + 4y - 3z - 3 = 0

7 0

4 years ago