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Effectus [21]
3 years ago
9

A pediatrician wishes to study how the average weight Y (in kilograms) of children changes during the first year of life. He plo

ts these averages versus the age X (in months) and decides to fit a least-squares regression line to the data with X as the explanatory variable and Y as the response variable. He computes the following quantities: r = correlation between X and Y= 0.84 x = mean of the values of X = 5.69 y = mean of the values of Y = 6.26 S_x = standard deviation of the values of X = 3.23 s_y = standard deviation of the values of Y = 2.04 The slope of the least-squares line is: A) 0.53.B) 0.64. C) 0.84. D) 2.04.
Mathematics
1 answer:
leonid [27]3 years ago
3 0

Answer:

Answer is option a ) 0.53

Step-by-step explanation:

slope = r*\frac{s_y}{s_x}

Given that a pediatrician wishes to study how the average weight Y (in kilograms) of children changes during the first year of life. He plots these averages versus the age X (in months) and decides to fit a least-squares regression line to the data with X as the explanatory variable and Y as the response variable.

He finds  the following quantities:

r = correlation between X and Y= 0.84

x = mean of the values of X = 5.69

y = mean of the values of Y = 6.26

S_x = standard deviation of the values of X = 3.23

s_y = standard deviation of the values of Y = 2.04

Using the formula for slope given above substitute to get

slope = 0.84*\frac{2.04}{3.23} \\=0.5305

round off to 0.53

Answer is option a ) 0.53

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z=1.04

And if we solve for a we got

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So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the finishing time of a population, and for this case we know the distribution for X is given by:

X \sim N(24.6,0.64)  

Where \mu=24.6 and \sigma=0.64

Solution to the problem

For this part we want to find a value a, such that we satisfy this condition:

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Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

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