Answer:
a. Describing a sample with mean and standard deviation.
Step-by-step explanation:
Statistics can be categorized into descriptive and inferential statistics.
descriptive statistics uses data for descriptions through numerical analysis. It can be further divided in four parts.
- Measures of Central Tendency ( Mean, Median, and Mode)
- Measures of Frequency (Count, Percent, Frequency)
- Measures of Position (Percentile Ranks, Quartile Ranks.)
- Measures of Dispersion ( Range, Standard Deviation)
Inferential statistics however is based on assumptions and conclusions and generalizations drawn from samples or checks.
options b to d are all examples of inferential statistics while option a is an example of descriptive statistics.
Answer:
22 hours (B)
Step-by-step explanation:
John's velocity = 55mph
Sally's velocity = 65mph
John's time taken = x
Sally's time taken = x - 4
since they must cover the same distance.
and, distance = vel × time
Sally's vel × time = John's vel × time
55x = 65(x-4)
55x = 65x - 220
-10x = -220
x = 22 hours.
Therefore, Sally catches up after 22 hours
The domain tells you about the independent variable, number of payments made. So the inequality should be
smallest number of payments made ≤ variable representing payments ≤ largest number of payments made.
The smallest number of payments is 0 and the largest is 8, so you'll have
<span><span>
0≤variable≤8</span></span>
Answer:
1 - 
12 - ?
4 - square root of 16
64 - 
16 - 
2.828 - square root of 8
Step-by-step explanation:
I need more terms to match
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.
N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v
// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.
// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}
