Answer:
Step-by-step explanation:
The minimum value of sinx is -1 when x = 3π/2, 7π/2, ...
In [2π, 4π), x = 7π/2
Answer:
2.5 second
Step-by-step explanation:
The equation is missing in the question.
The equation is,
, where 'h' is the height and 't' is time measured in second.
Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

Now the differentiating the equation with respect to time t, we get


For maximum height, 
So, 



Therefore, the ball takes 2.5 seconds time to reach the maximum height.
T<span>he number of questions Natalie answered incorrectly.</span>
Answer:
The answer is B if the octagon has side lengths of 8
The exact circumference of the circle is 
The approximate circumference of the circle is 
Explanation:
The diameter of the circle is 
Now, we shall find the circumference of the circle.
The formula to determine the circumference of the circle is given by

Where C is the circumference ,
is 3.14 and
is the diameter of the circle.
The exact circumference of the circle is given by

Multiply both numerator and denominator by 100, we get,

Converting
into mixed fraction, we get,

Thus, the exact circumference of the circle is 
The approximate value of the circumference can be determined by dividing the value 


Thus, the approximate circumference of the circle is 